1012 数字分类 (20 分)

#include
int main(void)
{
	int a1 = 0, a2 = 0, a3 = 0, a5 = 0;
	float a4 = 0.0;
	int cnt1, cnt2, cnt3, cnt4, cnt5;
	cnt1 = cnt2 = cnt3 = cnt4 = cnt5 = 0;
	int n;
	int count;
	int num = 0;
	int i = 0;
	int sum = 0;
	scanf_s("%d", &n);
	for (count = 1; count <= n; count++)
	{
		scanf_s("%d", &num);
		i = num % 5;
		switch (i)
		{
		case 0:
			if (num % 2 == 0)
			{
				a1 += num;
				cnt1++;
			}
			break;
		case 1:
			cnt2++;
			if (cnt2 % 2 != 0)
			{
				a2 += num;
			}
			else
			{
				a2 -= num;
			}
			break;
		case 2:
			cnt3++;
			a3 = cnt3;
			break;
		case 3:
			cnt4++;
			sum += num;
			break;
		case 4:
			cnt5++;
			if (cnt5 == 1)
				a5 = num;
			if (num > a5)
				a5 = num;
			break;
		}
	}
	if (cnt1 == 0)
		printf("N");
	else
		printf("%d", a1);
	if (cnt2 == 0)
		printf(" N");
	else
		printf(" %d", a2);
	if (cnt3 == 0)
		printf(" N");
	else
		printf(" %d", a3);
	if (cnt4 == 0)
		printf(" N");
	else
	{
		a4 = (double)sum / cnt4;
		printf(" %.1f", a4);
	}
	if (cnt5 == 0)
		printf(" N");
	else
		printf(" %d", a5);
	return 0;
}

这道题也比较简单

主要就只是对题目的翻译