1.用hive的rlike函数替换Oracle的regexp_like函数:
Oracle原有逻辑:
(CASE WHEN REGEXP_LIKE(column_a, '^([0]+|[1]+|[2]+|[3]+|[4]+|[5]+|[6]+|[7]+|[8]+|[9])') AND LENGTH(column_a)=8 THEN '人员代码' ELSE column_a END) AS C102,
迁移到hive中:
(CASE WHEN column_a RLIKE '^([0]+|[1]+|[2]+|[3]+|[4]+|[5]+|[6]+|[7]+|[8]+|[9])' AND LENGTH(column_a)=8 THEN '人员代码' ELSE column_a END) AS column_a,
2.hive获取指定日期所在季度:
floor(substr(column_b,6,2)/3.1)+1 || '季度' as column_b



