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名师互学网 > IT > 前沿技术 > 大数据 > 大数据系统

Oracle数据库训练

Oracle数据库训练

Oracle数据库查询训练

Oracle查询语句最后的练习
范围是scott用户专属自带的emp、dept和salgrade三张表


题目:

1.查询薪金高于在部门 30 工作的所有员工的薪金的员工姓名和薪金、部门名称、部门人数

SELECt e.ename,e.sal,d.dname,temp.count
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) COUNT
    FROM emp
    GROUP BY deptno
) temp
WHERe e.sal >ALL (SELECt sal FROM emp WHERe deptno = 30)
AND (e.deptno = temp.dno)
AND (e.deptno = d.deptno);

或者

SELECt e.ename,e.sal,d.dname,temp.count
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) COUNT
    FROM emp
    GROUP BY deptno
) temp
WHERe e.sal > (SELECt MAX(sal) FROM emp WHERe deptno = 30)
AND (e.deptno = temp.dno)
AND (e.deptno = d.deptno);



2.查询与 Scott 从事相同工作的所有员工姓名、职位、工资及部门名称、部门人数、领导姓名

SELECt e.ename,e.job,e.sal,d.dname,temp.count,m.ename
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) count 
    FROM emp
    GROUP BY deptno
) temp,emp m
WHERe (e.job IN (SELECt job FROM emp WHERe ename = 'SCOTT'))
AND (e.ename != 'SCOTT')
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno)
AND (e.mgr(+) = m.empno);



3. 查询薪金比 Smith 或 Allen 多的所有员工的编号、姓名、部门名称、领导姓名、部门人数、平均工资、最高和最低工资

SELECt e.empno,e.ename,d.dname,m.ename,temp.count,temp.avg,temp.max,temp.min
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) count,AVG(sal) avg,MAX(sal) max,MIN(sal) min
    FROM emp
    GROUP BY deptno
) temp,emp m
WHERe e.sal >ANY (SELECt sal FROM emp WHERe ename IN ('SMITH','ALLEN'))
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno)
AND (e.mgr(+) = m.empno);



4. 查询雇佣日期早于其直接上级的所有员工的编号、姓名、部门名称、部门位置、部门人数

SELECt e.empno,e.ename,d.dname,d.loc,temp.count
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) count
    FROM emp
    GROUP BY deptno
) temp,emp m
WHERe (e.mgr = m.empno)
AND (e.hiredate < m.hiredate)
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno);

5. 查询所有办事员的姓名及其部门名称、部门的人数,工资等级

SELECt e.ename,d.dname,temp.count,s.grade
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) count
    FROM emp
    GROUP BY deptno
) temp,salgrade s
WHERe (e.job = 'CLERK')
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno)
AND (e.sal BETWEEN s.losal AND s.hisal);



6. 查询所有部门的部门名称,部门位置和部门人数

SELECt d.dname,d.loc,temp.count
FROM dept d,(
    SELECt deptno dno,COUNT(empno) count
    FROM emp
    GROUP BY deptno
) temp
WHERe (d.deptno = temp.dno(+));


7. 查询雇员姓名中带 ‘K’ 字符的雇员姓名及其所在部门的人数

SELECt e.ename,temp.count
FROM emp e,(
    SELECt deptno dno,COUNT(empno) count
    FROM emp
    GROUP BY deptno
) temp
WHERe (e.ename LIKE '%K%')
AND (e.deptno = temp.dno);


8. 查询每个工资等级雇员的人数、最高工资,最低工资,平均工资

SELECt s.grade,COUNT(e.empno) count,MAX(e.sal) max,MIN(e.sal) min,TRUNC(AVG(e.sal)) avg
FROM emp e,salgrade s
WHERe e.sal BETWEEN s.losal AND s.hisal
GROUP BY s.grade
ORDER BY grade;



9. 查询会计部的所有雇员姓名、基本工资、雇佣日期、部门位置,工资等级,部门人数

SELECt e.ename,e.sal,e.hiredate,d.loc,s.grade,temp.count
FROM emp e,dept d,salgrade s,(
    SELECt deptno dno,COUNT(empno) count
    FROM emp
    GROUP BY deptno
) temp
WHERe (e.deptno = (SELECt deptno FROM dept WHERe dname = 'ACCOUNTING'))
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno)
AND (e.sal BETWEEN s.losal AND s.hisal)
ORDER BY s.grade;

10. 在 Oracle数据库 中有表 ’ test ',它包含属性 “ test_code”,” test_category ” 和 ” test_name”查询 test_category 取值为 ” MySQL ” 或 ” SQLServer ” 的行

SELECt *
FROM test
WHERe (test_category = 'MySQL') OR (test_category = 'SQLServer');

鉴于自己没这张表,所以没图,但是要会敲


11. 查询雇佣日期早于领导的员工的姓名、部门名称、部门人数

SELECt e.ename,d.dname,temp.count
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) count
    FROM emp
    GROUP BY deptno
) temp,emp m
WHERe (e.mgr = m.empno)
AND (e.hiredate < m.hiredate)
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno);



12. 统计有领导和没有领导的员工的人数和平均工资

SELECt COUNT(empno),TRUNC(AVG(sal)) FROM emp WHERe (mgr IS NOT NULL)
union
SELECt COUNT(empno),TRUNC(AVG(sal)) FROM emp WHERe (mgr IS NULL);


13. 列出薪金比部门30都多的所有员工的姓名、基本工资、部门位置、领导姓名、所在部门的人数及最高工资

SELECt e.ename,e.sal,d.loc,m.ename,temp.count,temp.max
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) count,MAX(sal) max
    FROM emp
    GROUP BY deptno
) temp,emp m
WHERe (e.sal >ALL (SELECt sal FROM emp WHERe deptno = 30))
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno)
AND (e.mgr = m.empno);

14. 查询部门20中,雇佣年限超过37年而工资在2000以下的雇员信息

SELECt *
FROM emp
WHERe (deptno = 20)
AND (TRUNC(MONTHS_BETWEEN(SYSDATE,hiredate)/12) > 37)
AND (sal < 2000);



15. 查询至少有一个员工的所有部门

SELECt deptno,COUNT(empno)
FROM emp e
HAVINg COUNT(empno) > 0
GROUP BY deptno;



16. 查询基本工资比 “ Smith ” 多的所有员工信息

SELECt *
FROM emp
WHERe sal > (SELECt sal FROM emp WHERe ename = 'SMITH')
ORDER BY sal,deptno;



17. 查询所有员工的姓名及其领导的姓名

SELECt e.ename,m.ename lead
FROM emp e,emp m
WHERe e.mgr = m.empno(+);



18. 查询雇佣日期早于其领导的所有员工信息

SELECt *
FROM emp e,emp m
WHERe (e.mgr = m.empno)
AND (e.hiredate < m.hiredate);

19.查询最高基本工资低于5000的所有岗位名称及从事此工作的雇员姓名,其所在的部门名称、部门人数、部门平均工资

SELECt e.ename,d.dname,temp.count,temp.avg
FROM emp e,dept d,(
    SELECt deptno dno,COUNT(empno) count,TRUNC(AVG(sal)) avg
    FROM emp
    GROUP BY deptno
)temp
WHERe (e.job IN (SELECt job FROM emp GROUP BY job HAVINg COUNT(empno) < 5000 ))
AND (e.deptno = d.deptno)
AND (e.deptno = temp.dno);


oracle数据库告一段落

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