python 获取函数类的源码

import inspect


def funCase():
    a = 1
    b = 1
    print("OK")
    funCase2()


def funCase2():
    print("cc")


class classCase(object):
    def __init__(self):
        self.start = 1

    def fun(self):
        print("sd")


funCaseResult = inspect.getsource(funCase)
funCase2Result = inspect.getsource(funCase2)
classCaseResult = inspect.getsource(classCase)

print("----------funCaseResult------------")
print(funCaseResult)
print("----------funCase2Result------------")
print(funCase2Result)
print("----------classCaseResult------------")
print(classCaseResult)

----------funCaseResult------------
def funCase():
    a = 1
    b = 1
    print("OK")
    funCase2()

----------funCase2Result------------
def funCase2():
    print("cc")

----------classCaseResult------------
class classCase(object):
    def __init__(self):
        self.start = 1

    def fun(self):
        print("sd")


Process finished with exit code 0