指针小训练（1）

#include

void main(void)
{
    int a[5] = {1, 2, 3, 4, 5};

    printf("%dn",&a);//6618672
    printf("%dn",*a);//1

    printf("%dn",(int *)a);//6618672
    printf("%dn",*(int *)a);//1

    printf("%dn",&a+1);//6618692
    printf("%dn",(int *)(&a+1));//6618692
    printf("%dn",*(int *)(&a+1));//0
    printf("%dn",*(&a+1));//6618692

    printf("%dn",*(a+1));//2


    int *ptr =  (int *)(&a + 1); // &a取址后以a[0-4]整个数组为步进，a以a[0]也就是int为步进
    printf("%dn",*ptr);//0
    printf("%dn",&ptr);//6618664
    printf("%dn",*ptr+1);//1
    printf("%dn",*(ptr+1));//0
    printf("%dn",*(ptr-1));//5

    printf("%d %d" , *(a + 1), *(ptr - 1));//2 5
}