class Node
{
public:
int val;
vector children;
Node() {}
Node(int _val) {
val = _val;
}
Node(int _val, vector _children) {
val = _val;
children = _children;
}
};
二、根据层序遍历的结果数组,构造 N叉树:
#include三、运行结果:#include using std::cout; using std::endl; using std::string; using std::vector; class Node { public: int val; vector children; Node() {} Node(int _val) { val = _val; } Node(int _val, vector _children) { val = _val; children = _children; } }; class Solution { public: vector preorder(Node* root) { if (root == NULL) return {}; cout << "enter:" << root->val << endl; childarr.push_back(root->val); for (Node* child : root->children) { preorder(child); } cout << "Leave:" << root->val << endl; return childarr; } private: vector childarr; }; // 1 // / | // 3 2 4 // / // 5 6 int main() { //给出N叉树的层序遍历 数组 vector root = { 1, NULL, 3, 2, 4, NULL, 5, 6 }; //根据层序遍历的结果 ,构造出多叉树 Node Tree[6]; for (int i=0,j=0;i<6 && j<8 ;i++,j++) { while (root[j]==NULL) { j++; } Tree[i].val = root[j]; } Tree[0].children.push_back(&Tree[1]); Tree[0].children.push_back(&Tree[2]); Tree[0].children.push_back(&Tree[3]); Tree[1].children.push_back(&Tree[4]); Tree[1].children.push_back(&Tree[5]); Solution todo; //N叉树的前序遍历 vector result = todo.preorder(Tree); //前序遍历的结果 打印 for (auto it = result.begin();it!=result.end();it++) { cout<<" "<<*it; } }
结果中,打印出的enter 和 Leave 是 深度优先遍历的 进入 和 回溯 的节点。
在 for 循环里面和外面 唯一的区别就 是对根节点的处理。
如果更改成在for循环里面打印,结果如下:
class Solution {
public:
vector preorder(Node* root) {
if (root == NULL) return {};
childarr.push_back(root->val);
//在 for 循环里 打印
for (Node* child : root->children)
{
cout << "enter:" << child->val << endl;
preorder(child);
cout << "Leave:" << child->val << endl;
}
return childarr;
}
private:
vector childarr;
};



