13、函数运行时间

给定一系列描述函数进入和退出的时间，问每个函数的运行时间是多少。

输入s=[“F1 Enter 10”,“F2 Enter 18”,“F2 Exit 19”,“F1 Exit 20”],则输出[“F1|10”,F2|1],即F1从10时刻进入，20时刻退出，
运行时长为10，F2从18时刻进入19时刻退出，运行时长为1
输入s=[“F1 Enter 10”,“F1 Exit 19”,“F1 Enter 18”，“F1 Exit 20”],则输出10

#代码演示
class Two:
    def __init__(self):
        self.l = []
        self.enter_list = []
        self.exit_list = []
        self.d = {}
    def two(self,s):
        for i in s:
            self.l.append(i[0:2])
        se = set(self.l)
        se = list(se)
        se.sort()
        if len(se)>1:
            for i in se:
                su = []
                for j in s:
                    if j[0:2] == i:
                        su.append(j[-2::])
                self.d[i] = int(su[1])-int(su[0])
            return self.d
        else:
            rult = 0
            for i in s:
                if "Enter" in i:
                    self.enter_list.append(int(i[-2::]))
                else:
                    self.exit_list.append(int(i[-2::]))
            for i in range(len(self.enter_list)):
                rult1 = self.exit_list[i]-self.enter_list[i]
                rult += rult1

            return rult
s=["F1 Enter 10","F2 Enter 18","F2 Exit 19","F1 Exit 20"]
solution = Two()
print(solution.two(s))