由千峰教育笔记整理而成
and逻辑与 or逻辑或 not逻辑非
逻辑运算符的运算结果也是返回True False
n1 = 8 n2 = 5 n3 = 3 result = n1 >= (n2 + n3) and n1 > n2 print(result)
分析True&True--->True
运行结果为True
#判断是否存在用户 or
username = '' email = '63478364@qq.com' result = username == 'admin123' or email == '63478364@qq.com' print(result)
运行结果为True
flag = False
result = not flag # not就是取反
print('not--->', result)



