11、最接近target的值

给出一个数组，在数组中找到2个数，使得它们的和最接近但不超过目标值，返回它们的和。

输入target = 15，array= [1,3,5,11,7],输出14，11+3=14，输入target=16和array=[1,3,5,11,7],输出16，11+5=16

#代码实现
class Solution:
    def __init__(self,array,target):
        self.array = array
        self.target = target
        self.T_F = False
        self.num_list = []
        self.num_list.append(self.target)
        self.font = 0
        self.font_rult =0
    def two_sum(self):
        for i in range(len(array)):
            for j in array[i+1::]:
                num = array[i] + j
                if num == target:
                    self.T_F = True
                    print(num,"{}+{}={}".format(j,array[i],num))
                else:
                    self.num_list.append(num)
                self.num_list.sort()
                font = self.num_list[self.num_list.index(self.target) - 1]
                font_rult = "{}+{}={}".format(j,self.array[i],font)
        if self.T_F == False:
            print(self.font,self.font_rult)


array = [1,3,5,11,7]
target = 16
solution = Solution(array,target)
solution.two_sum()