2021-10-08

#include 
#include 
using namespace std;
int currency[]={1,2,4,10,20,40,100,200,400,1000,2000};
long long num[6001];
int main()
{
	memset(num,0,sizeof(num));
	num[0]=1;
	for(int i=0;i<11;i++)
	for(int j=currency[i];j<=6000;j++)
	num[j]+=num[j-currency[i]];//类似于某种递归 ,状态转移方程 
	double a;
	while(~scanf("%lf",&a)&&a)
	{
		int aa=(int)(a*100+0.5);
		printf("%6.2lf%17lldn",a,num[aa/5]);
	}
	return 0;
}