思路:
队列:先进先出 栈:先进后出
push(): 插入stack1
pop(): 当stack2不为空,弹出stack2栈顶元素,如果stack2为空,将stack1全部出栈入栈stack2,再弹出stack2栈顶元素
class Solution
{
public:
void push(int node) {
stack1.push(node);
}
int pop() {
if(stack2.empty()&&stack1.empty())
return -1;
if(stack2.empty()){
while(!stack1.empty()){
int top = stack1.top();
stack1.pop();
stack2.push(top);
}
}
int top = stack2.top();
stack2.pop();
return top;
}
private:
stack stack1;
stack stack2;
};
时间复杂度: push O(1) pop() O(1)



