八位二进制数转化为十进制数输出

#include "iostream"

using namespace std;

//计算x的n次方
double power(double x,int n);

int main()
{
    int value=0;

    cout<<"Enter an 8 bit binary number:";
    for(int i=7;i>=0;i--)
    {
        char ch;
        cin>>ch;
        if(ch=='1')
            value+=static_cast(power(2,i));
    }
    cout<