class Solution:
def longestPalindrome(self, s: str) -> str:
if not s:
return ''
dp = [[False for i in range(len(s))]for i in range(len(s))]
for i in range(len(s)):
dp[i][i] = True
cur_start_index = 0
max_length = 1
for j in range(1,len(s)):
for i in range(j):
if s[i] == s[j]:
if j-i < 3:
dp[i][j] = True
else:
dp[i][j] = dp[i+1][j-1]
if dp[i][j]:
cur_length = j-i+1
if cur_length > max_length:
max_length = cur_length
cur_start_index = i
return s[cur_start_index:cur_start_index+max_length]
class Solution:
def lengthOfLIS(self, nums: List[int]) -> int:
dp = [1 for i in range(len(nums))]
for i in range(1,len(nums)):
for j in range(i):
if nums[j] < nums[i]:
dp[i] = max(dp[j] + 1,dp[i])
return max(dp)
3、最长连续子数组
class Solition: def maxlength(self,arr): if len(arr) == 0: return 0 if len(arr) == 1: return 1 res = [] length = 0 for i in srr: while i in res: res.pop(0) res.append(i) length = max(length,len(res)) return length



