最长回文子串-最长公共子序列

package arithmetic.dynamicplan;

import java.util.Arrays;

public class Demo01 {

    
    public static void main(String[] args) {
        String A = "aacd";
        System.out.println(getLongestPalindrome(A, A.length()));
    }

    public static int getLongestPalindrome(String A, int n) {
        // write code here
        int[][] L = new int[n][n];
        for(int i = 0; i < n; ++i){
            L[i][i] = 1;
        }
        int i, j = 1;
        while (j < n){
            i = j - 1;
            while(i >= 0){
                //  中间是连续回文，且ij元素相同
                if(A.charAt(i) == A.charAt(j) && L[i + 1][j - 1] == j - i - 1){
                    L[j][i] = L[i][j] = L[i + 1][j - 1] + 2;
                //  中间不是连续回文，无论ij元素是否相同
                }else{
                    L[j][i] = L[i][j] = Math.max(L[i][j - 1],L[i + 1][j]);
                }
                --i;
            }
            ++j;
        }
        for(i = 0; i < n; i++){
            System.out.println(Arrays.toString(L[i]));
        }
        return L[0][n-1];
    }

}

package arithmetic.dynamicplan;

import java.util.Arrays;

public class Demo02 {

    
    public static void main(String[] args) {
        int[] arr1 = {2,1,3,5,6,7,2};
        int[] arr2 = {3,9,5,2,6,5};
        System.out.println(getLongestSubsequence(arr1, arr2));
    }

    public static int getLongestSubsequence(int[] arr1,int[] arr2) {
        int[][] L = new int[arr1.length + 1][arr2.length + 1];
        for(int i = 1; i <= arr1.length; ++i){
            for(int j = 1; j <= arr2.length; ++j){
                if(arr1[i - 1] == arr2[j - 1]){
                    L[i][j] = L[i - 1][j - 1] + 1;
                }else{
                    L[i][j] = Math.max(L[i][j - 1], L[i - 1][j]);
                }
            }
        }
        for(int i = 0; i <= arr1.length; i++){
            System.out.println(Arrays.toString(L[i]));
        }
        return L[arr1.length][arr2.length];
    }
}