使用命令行自动化测试工具pexpect登录ftp服务器172.20.17.200，并镜像projects目录。
参考
#!/usr/bin/env python3# -*- coding: utf-8 -*-# Author: xurongzhong#126.com wechat:pythontesting qq:37391319# 技术支持 钉钉群：21745728(可以加钉钉pythontesting邀请加入) # qq群：144081101 591302926 567351477# CreateDate: 2018-07-27import pexpectclass Lftp(object):
client = None @classmethod
def connect(cls, ip, username="andrew", password="654321_", prompt='~>',
silent=False):
child = pexpect.spawn('lftp {}:{}@{}'.format(username, password, ip),
maxread=5000)
i = 1
# Enter password
while i != 0:
i = child.expect([prompt, pexpect.TIMEOUT]) if not silent:
print(child.before.decode('utf-8'), child.after.decode('utf-8')) if i == 0: # find prompt
pass
else:
raise Exception('ERROR TIMEOUT! LFTP could not login. ')
Lftp.client = child @classmethod
def command(cls, cmd, prompt='~>', silent=False):
Lftp.client.buffer = b''
Lftp.client.send(cmd + "r") # Lftp.client.setwinsize(400,400)
Lftp.client.expect([prompt,]) if not silent:
print(Lftp.client.before.decode('utf-8'),
Lftp.client.after.decode('utf-8')) return Lftp.client.before, Lftp.client.after @classmethod
def close(cls):
Lftp.client.close()
c = Lftp()
c.connect('172.20.17.200')
c.command("ls -l")
c.command("mirror projects")
c.close()最新代码地址
注意：该例子用ftplib更快捷，但是对于不支持网络协议的纯命令行交互，pexpect则能大行其道。另外对于网络设备，pexpect能用几乎完全一样的代码支持telnet，ftp，ssh，且灵活性更好。
2018-07-20 用flask和matplotlib画出正弦曲线用flask和matplotlib画出1-10的正弦曲线，并用flask在web进行展示，如下：
图片.png
参考答案：
import matplotlib
matplotlib.use('agg')import matplotlib.pyplot as pltfrom flask import Flaskimport numpy as npimport io
app = Flask(__name__)@app.route('/plot')def build_plot():
# Generate the plot
x = np.linspace(0, 10)
line, = plt.plot(x, np.sin(x))
f = io.BytesIO()
plt.savefig(f, format='png') # Serve up the data
header = {'Content-type': 'image/png'}
f.seek(0)
data = f.read() return data, 200, headerif __name__ == '__main__':
app.run(host='0.0.0.0',port=8000, debug=True)最新代码地址
参考资料
https://stackoverflow.com/questions/35737116/runtimeerror-invalid-display-variable
http://www.fivecomputers.com/serving-dynamic-charts-with-flask.html
https://stackoverflow.com/questions/41459657/how-to-create-dynamic-plots-to-display-on-flask
http://hplgit.github.io/web4sciapps/doc/pub/._web4sa_flask013.html
http://dataviztalk.blogspot.com/2016/01/serving-matplotlib-plot-that-follows.html
https://github.com/realpython/flask-matplotlib/blob/master/app.py
https://gist.github.com/wilsaj/862153
https://www.hackster.io/mjrobot/from-data-to-graph-a-web-journey-with-flask-and-sqlite-4dba35
一、条件：
df1 = pd.Dataframe(np.arange(12.).reshape((3, 4)), columns=list('abcf'))
df2 = pd.Dataframe(np.arange(20.).reshape((4, 5)), columns=list('abcde'))
1, 求df1 + df2的计算结果：
参考答案：
a b c d e f0 0.0 2.0 4.0 NaN NaN NaN1 9.0 11.0 13.0 NaN NaN NaN2 18.0 20.0 22.0 NaN NaN NaN3 NaN NaN NaN NaN NaN NaN
2, 求df1.add(df2)的计算结果：
参考答案：
a b c d e f0 0.0 2.0 4.0 NaN NaN NaN1 9.0 11.0 13.0 NaN NaN NaN2 18.0 20.0 22.0 NaN NaN NaN3 NaN NaN NaN NaN NaN NaN
3, 求df1.add(df2, fill_value=0)的计算结果：
参考答案：
a b c d e f0 0.0 2.0 4.0 3.0 4.0 3.01 9.0 11.0 13.0 8.0 9.0 7.02 18.0 20.0 22.0 13.0 14.0 11.03 15.0 16.0 17.0 18.0 19.0 NaN
二、条件：
df1 = pd.Dataframe(np.arange(12.).reshape((3, 4)), columns=list('abcf'))
df2 = pd.Dataframe(np.arange(20.).reshape((4, 5)), columns=list('abcde'))
df1.drop(0, inplace=True)
df2.drop(2, inplace=True)
1, 求df1 + df2的计算结果：
参考答案：
a b c d e f0 NaN NaN NaN NaN NaN NaN1 9.0 11.0 13.0 NaN NaN NaN2 NaN NaN NaN NaN NaN NaN3 NaN NaN NaN NaN NaN NaN
2, 求df1.add(df2)的计算结果：
参考答案：
a b c d e f0 NaN NaN NaN NaN NaN NaN1 9.0 11.0 13.0 NaN NaN NaN2 NaN NaN NaN NaN NaN NaN3 NaN NaN NaN NaN NaN NaN
3, 求df1.add(df2, fill_value=0)的计算结果：
参考答案：
a b c d e f0 0.0 1.0 2.0 3.0 4.0 NaN1 9.0 11.0 13.0 8.0 9.0 7.02 8.0 9.0 10.0 NaN NaN 11.03 15.0 16.0 17.0 18.0 19.0 NaN
图片.png
参考代码：
def send_mail(recipients, sub, content, from_name='比对测试',server="smtp.126.com",
files=[]):
EMAIL_SEND_USER = os.environ.get('EMAIL_SEND_USER')
EMAIL_SEND_PASSPORT = os.environ.get('EMAIL_SEND_PASSPORT')
msg = MIMEMultipart()
msg.attach(MIMEText(content, 'plain'))
msg['Subject'] = sub
msg['From'] = "{}<{}>".format(from_name, EMAIL_SEND_USER)
msg['To'] = ", ".join(recipients) try:
s = smtplib.SMTP()
s.connect(server)
s.login(EMAIL_SEND_USER, EMAIL_SEND_PASSPORT) for f in files or []: with open(f, "rb") as fil:
part = MIMEApplication(
fil.read(),
Name=os.path.basename(f)
) # After the file is closed
part['Content-Disposition'] = 'attachment; filename="%s"' % os.path.basename(f)
msg.attach(part)
print("send email to {}".format(recipients))
s.sendmail(EMAIL_SEND_USER, recipients, msg.as_string())
s.close() return True
except Exception as e:
print(str(e)) return False
if __name__ == '__main__': if send_mail(['xurongzhong@sensetime.com'],"活体比对测试结果", "测试结果",
files=[r'output.xls']):
print("发送成功")
作者：python作业AI毕业设计
链接：https://www.jianshu.com/p/1872da4c9976
