Python Day 8
Problem 1: FactorialWrite a factorial function that takes a positive integer, N as a parameter and prints the result of N!
Solution:
def factor(n):
a=1
for i in range (1,n+1):
a=a*i
print(a)
factor(3)
6
factor(5)
120
- If n is between 0 to 12, print Young.
- If 13 and 19, print Teenager.
- Otherwise, print adult.
- If age is smaller than 0, that’s Not valid
def age(n):
if n<=0 :
print ("Not valid")
elif n in range (0,14):
print ("Young")
elif n in range (13,19):
print ("Teenager")
else:
print("adult")
age(-1)
Not valid
[caption id=“attachment_1642” align=“alignnone” width=“500”]
cbaquiran / Pixabay[/caption]
Problem 3: Do LoopGiven an integer, n, print its first 10 multiples. Each multiple n x i , should be printed on a new line in the form: n x i = result
def mul2(n):
count=0
while count <11:
print(count, "x", n, "=", count*n)
count +=1
mul2(3)
0 x 3 = 0
1 x 3 = 3
2 x 3 = 6
3 x 3 = 9
4 x 3 = 12
5 x 3 = 15
6 x 3 = 18
7 x 3 = 21
8 x 3 = 24
9 x 3 = 27
10 x 3 = 30
Given a string, S, of length N that is indexed from 0 to N-1 , print its even-indexed and *odd-indexed *characters as 2 space-separated strings on a single line
def sep_string(a):
l=list(a)
l2=list()
l1=list()
index=0
for letter in l:
if index %2 ==1:
l1.append(letter)
else:
l2.append(letter)
index +=1
string_even = " ".join(l2)
string_odd=" ".join(l1)
print(string_even.replace(" ", ""), " ", string_odd.replace(" ",""))
sep_string("Wonderful")
Wnefl odru
Happy Studying! 酪
