Python 小目标10

Python Day 16

suppose we want to find the distinct average of a list.
Key: we need to use SET function.

def average(array):
    sum1=sum(set(array))
    n=len(set(array))
    return(sum1/n)

[caption id=“attachment_2136” align=“alignnone” width=“650”]

12019 / Pixabay[/caption]

Before we solve the challenge, we will go over some basic Set operations in Python.

Set:

a=input()
5 4 3 2
list1=a.split()
print(list1)
['5', '4', '3', '2']

MAP: convert the strings to integers

newlist=list(map(int,list1))
pprint(newlist)
[5,4,3,2]

Creating set

#1. Directly assigning values to a set
myset = {1, 2} 

#2.Creating a set from a list
myset = set()  # Initializing a set
myset = set(['a', 'b']) 
myset
{'a', 'b'}

Modifying Sets

We will show the functions: Add, Update, and Remove

#1.Add values to a set
myset.add("c")myset{"a", "b", "c"}

#2. Update a set value
myset.update([1,2,3,4]) #update only works for iterable objects
myset
{"a", "b", "c", 1,2,3,4}

#3. Remove items
myset.discar(1)
myset
{"a", "b", "c", 2,3,4} 

Common Set Operations:

We will introduce 3 basic set operations: Union, Intersection, Difference.

#1. Union: values in a or b
a = {2, 4, 5, 9}
b = {2, 4, 11, 12}
a.union(b) #order doesn't matter
{2, 4, 5, 9, 11, 12}

#2. Intersection: values in a and b
a.intersection(b) #order doesn't matter
{2,4}

#3. Difference: values in a but not in b
a.difference(b) #order does matter
{9,5}

Now, back to our original challenge, we will use the difference function to solve the problem

a,b = [set(input().split()) for _ in range(4)][1::2]
ad=a.difference(b)
bd=b.difference(a)
c=ad.union(bd)
print('n'.join(sorted(c, key=int)))

#Alternative solution
print ('n'.join(sorted(a^b, key=int)))

Reference:
https://www.hackerrank.com/challenges/py-set-add/problem