SQL> SELECt KTUXEUSN, KTUXESLT, KTUXESQN, 2 KTUXESTA Status, KTUXECFL Flags ,KTUXESIZ 3 FROM x$ktuxe 4 WHERe ktuxesta!='INACTIVE'; KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- ---------- ---------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2819919 39 0 502 ACTIVE NONE 1 43 45 480 ACTIVE NONE 0
SQL> / KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- ---------- ---------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2819919<----该值没减小。 39 0 502 ACTIVE NONE 1 43 45 480 ACTIVE NONE 0
查询v$px_session和v$fast_start_servers,显示很多并行进程在rollback，根据以往的工程经验：
于是改为
SQL>alter system set fast_start_parallel_rollback=false scope=both;
之后，再次运行
SQL> SELECt KTUXEUSN, KTUXESLT, KTUXESQN, 2 KTUXESTA Status, KTUXECFL Flags ,KTUXESIZ 3 FROM x$ktuxe 4 WHERe ktuxesta!='INACTIVE'; KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- -------------------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2033516 35 29 502 ACTIVE NONE 1 SQL> / KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- -------------------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2033433<---该值不断变小。 35 29 502 ACTIVE NONE 1
使用如下脚本查看回滚完毕的预计时间（以天为单位）：
SQL> set serveroutput on
SQL> declare
2 l_start number;
3 l_end number;
4 begin
5 select ktuxesiz into l_startfrom x$ktuxe where KTUXEUSN=13 and KTUXESLT=5;
6 dbms_lock.sleep(60);
7 select ktuxesiz into l_endfrom x$ktuxe where KTUXEUSN=13 and KTUXESLT=5;
8 dbms_output.put_line('time estDay:'|| round(l_end/(l_start -l_end)/60/24,2));
9 end;
10 /
time est Day:.21
24*0.21=5.04小时。即：预计5.04小时后回滚完毕。
另外注意：在其他环境使用时，请注意替换KTUXEUSN=13和KTUXESLT=5
