如何统计全天各个时间段产品销量情况（sqlserver）

数据库环境：SQL SERVER 2005

现有一个产品销售实时表，表数据如下：

字段name是产品名称，字段type是销售类型，1表示售出，2表示退货，字段num是数量，字段ctime是操作时间。

要求：

　　在一行中统计24小时内所有货物的销售（售出，退货）数据，把日期考虑在内。

分析：

　　这实际上是行转列的一个应用，在进行行转列之前，需要补全24小时的所有数据。补全数据可以通过系统的数字辅助表

spt_values来实现，进行行转列时，根据type和处理后的ctime分组即可。

1.建表，导入数据

CREATE TABLE snake (name VARCHAr(10 ),type INT,num INT, ctime DATETIME )
INSERT INTO snake VALUES(' 方便面', 1,10 ,'2015-08-10 16:20:05')
INSERT INTO snake VALUES(' 香烟A ', 2,2 ,'2015-08-10 18:21:10')
INSERT INTO snake VALUES(' 香烟A ', 1,5 ,'2015-08-10 20:21:10')
INSERT INTO snake VALUES(' 香烟B', 1,6 ,'2015-08-10 20:21:10')
INSERT INTO snake VALUES(' 香烟B', 2,9 ,'2015-08-10 20:21:10')
INSERT INTO snake VALUES(' 香烟C', 2,9 ,'2015-08-10 20:21:10')

2.补全24小时的数据

WITH  x0
     AS ( SELECt  number AS h
 FROM   master..spt_values
 WHERe  type = 'P'
     AND number >= 0
     AND number <= 23
),
    x1
     AS ( SELECt DISTINCT
     ConVERT(VARCHAr(100), ctime, 23) AS d
 FROM   snake
),
    x2
     AS ( SELECt  x1.d ,
     x0.h
 FROM   x1
     CROSS JOIN x0
),
    x3
     AS ( SELECt  name ,
     type ,
     num ,
     DATEPART(hour, ctime) AS h
 FROM   snake
),
    x4
     AS ( SELECt  x2.d ,
     x2.h ,
     x3.name ,
     x3.type ,
     x3.num
 FROM   x2
     LEFT JOIN x3 ON x3.h = x2.h
)

3.行转列

SELECt ISNULL([0], 0) AS [00] ,
      ISNULL([1], 0) AS [01] ,
      ISNULL([2], 0) AS [02] ,
      ISNULL([3], 0) AS [03] ,
      ISNULL([4], 0) AS [04] ,
      ISNULL([5], 0) AS [05] ,
      ISNULL([6], 0) AS [06] ,
      ISNULL([3], 7) AS [07] ,
      ISNULL([8], 0) AS [08] ,
      ISNULL([9], 0) AS [09] ,
      ISNULL([10], 0) AS [10] ,
      ISNULL([3], 11) AS [11] ,
      ISNULL([12], 0) AS [12] ,
      ISNULL([13], 0) AS [13] ,
      ISNULL([14], 0) AS [14] ,
      ISNULL([3], 15) AS [15] ,
      ISNULL([16], 0) AS [16] ,
      ISNULL([17], 0) AS [17] ,
      ISNULL([18], 0) AS [18] ,
      ISNULL([19], 15) AS [19] ,
      ISNULL([20], 0) AS [20] ,
      ISNULL([21], 0) AS [21] ,
      ISNULL([22], 0) AS [22] ,
      ISNULL([23], 15) AS [23] ,
      type ,
      d AS date
  FROM  ( SELECt  d ,
     h ,
     type ,
     num
FROM   x4
      ) t PIVOT( SUM(num) FOR h IN ( [0], [1], [2], [3], [4], [5], [6],
 [7], [8], [9], [10], [11], [12],
 [13], [14], [15], [16], [17], [18],
 [19], [20], [21], [22], [23] ) ) t
  WHERe  type IS NOT NULL

来看一下最终效果，只有1天的数据，可能看起来不是很直观。

本文的技术点有2个：

　　1.利用数字辅助表补全缺失的记录

　　2.pivot行转列函数的使用

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