Java硬币翻转倍数递增试算实例

//有何不足或者问题希望能够得到各位的多多指正，不胜感激

复制代码 代码如下:
import java.util.Scanner;

public class CoinTurn {

 private static int[] intCoins;

 public static void main(String[] args) {
  // TODO Auto-generated method stub
  int coinNum = inputNum();
  intCoins = new int[coinNum];

  
  for (int i = 0; i < intCoins.length; i++) {
   intCoins[i] = 0;// 初始化全部朝下，即背面0
  }

  doTurnCoin();

  int resutltCoin = getCoinNum();

  System.out.println("result coin about 1 nums = " + resutltCoin);// 输出最终正面朝上的个数

 }

 private static void doTurnCoin() {
  
  for (int i = 1; i < intCoins.length; i++) {// 确定倍数

   for (int j = i - 1; j < intCoins.length; j++) {// 循环翻转
    if (j % i == 0) { // 硬币序列数是当前次数的倍数，则翻转
     if (intCoins[j] == 0) {
      intCoins[j] = 1;
     } else {
      intCoins[j] = 0;
     }
    }

   }
  }
 }

 private static int getCoinNum() {
  int countNum = 0;// 记录最终硬币正面个数
  StringBuffer strB = new StringBuffer();
  for (int a : intCoins) {
   strB.append(a + "");
   if (1 == a)
    countNum++;
  }
  System.out.println("int[] ==  " + strB);// 输出数组的结果
  return countNum;
 }

 
 private static int inputNum() {
  System.out.println("input coin num: ");
  Scanner input = new Scanner(System.in);
  return input.nextInt();
 }

}