java大数乘法的简单实现 浮点数乘法运算

复制代码 代码如下:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.regex.Matcher;
import java.util.regex.Pattern;


public class BigNumber {
    public static void main(String[] args) throws IOException {
        System.out.println("Input two large integers:");
        BufferedReader buffer = new BufferedReader(new InputStreamReader(System.in));
        String[] strArray = buffer.readLine().split("\*");
        System.out.println(bigNumberMultiply(strArray[0], strArray[1]));
    }

    
    private static String bigNumberMultiply(String first, String second) {
        // 正负号判断标志
        boolean flag = false;

        if (first.charAt(0) == '-') {
            flag = !flag;
            first = first.substring(1);
        }

        if (second.charAt(0) == '-') {
            flag = !flag;
            second = second.substring(1);
        }

        // 小数点的位置
        int aPoints = first.length() - first.indexOf('.') - 1;
        int bPoints = second.length() - second.indexOf('.') - 1;
        int pointPos = aPoints + bPoints; // 结果的小数点位置

        // 删除小数点
        StringBuffer aBuffer = new StringBuffer(first.replaceAll("\.", ""));
        StringBuffer bBuffer = new StringBuffer(second.replaceAll("\.", ""));

        int[] a = string2IntArray(aBuffer.toString());
        int[] b = string2IntArray(bBuffer.toString());

        int[] result = new int[a.length + b.length - 1]; // 保存结果的数组

        // 计算
        for (int i = 0; i < a.length; i++) {
            for (int j = 0; j < b.length; j++) {
                result[i + j] += a[i] * b[j];
            }
        }

        // result中的某一位大于9的话需要进位
        for (int i = result.length - 1; i >= 0; --i) {
            if (result[i] > 9) {
                result[i - 1] += result[i] / 10;
                result[i] = result[i] % 10;
            }
        }

        StringBuffer buffer = new StringBuffer(); // 将result数组转换为字符串
        for (int i = 0; i < result.length; ++i) {
            // 添加小数点
            if(result.length - i == pointPos) {
                buffer.append(".");
            }
            buffer.append(String.valueOf(result[i]));
        }

        if (buffer.indexOf(".") != -1)
        {
            // 删除最开始的0
            int i = 0;
            while (i < buffer.length()) {
                if (buffer.length() > 2 && buffer.charAt(i+1) == '.') { // 小数点前只有一个数 0.
                    break;
                } else if (buffer.charAt(i) == '0') { // 删除最前边的0
                    buffer.deleteCharAt(i);
                    i = 0;
                    continue;
                } else { // 当第一位不是0的时候
                    break;
                }
            }

            // 删除末尾的0
            i = buffer.length() - 1;
            while (i >= 0) {
                if (buffer.length() > 2 && buffer.charAt(i-1) == '.') { // 小数点后直接是数字
                    break;
                } else if (buffer.charAt(i) == '0') { // 删除末尾的0
                    buffer.deleteCharAt(i);
                    i = buffer.length() - 1;
                    continue;
                } else { // 当最后一位不是0的时候
                    break;
                }
            }
        }

        // 根据符号位, 返回值的正负标志
        if (flag) {
            return "-" + buffer.toString();
        } else {
            return buffer.toString();
        }
    }

    
    private static int[] string2IntArray(String number) {
        // 判断输入是否符合浮点数的要求
        Pattern pattern = Pattern.compile("^(-?\d+|\d*)\.?\d*$");
        Matcher matcher = pattern.matcher(number);
        if (!matcher.find()) {
            throw new IllegalArgumentException("输入的数不正确!");
        }

        int[] result = new int[number.length()];
        for (int i = 0; i < number.length(); i++) {
            result[i] = (int) (number.charAt(i) - '0');
        }
        return result;
    }
}

运行结果如下:

1. 错误输入的判断
复制代码 代码如下:
Input two large integers:
1a*a22
Exception in thread "main" java.lang.IllegalArgumentException: 输入的数不正确!
at BigNumber.string2IntArray(BigNumber.java:132)
at BigNumber.bigNumberMultiply(BigNumber.java:54)
at BigNumber.main(BigNumber.java:22)


 2. 带负数的运算, 前后带有0的情况
复制代码 代码如下:
Input two large integers:
-23424.2300*02345.23400000
-54935300.61982

 python中计算的结果如下
复制代码 代码如下:
Python 2.6.5
>>> -23424.2300*02345.23400000
-54935300.619819999

 可以看出python的结果是有失真的