Java中使用json与前台Ajax数据交互的方法

本文主要为大家分享了Ajax获取显示Json数据的一种方法，供大家参考，具体内容如下 
 1、首先前台用Ajax，其中注意dataType一定要选择json方式，Action成功返回给页面的Json内容是这样的[{"number":"V006","names":"LiLei"}],可见comment['names']对应"names":"LiLei"，comment['number']对应"number":"V006"。

$.ajax({
  type: "post",
   url:'apply/mystudent.action?',
  cache: false,
  dataType : "json",
  success: function(data){
   
   $.each(data, function(commentIndex, comment){
  
     alert("姓名"+ comment['names']);
 
     alert("学号"+comment['number']);

  });
   }
  }); 

2、Ajax的URL指向在java的action中mystudent方法，返回的list其实是一个对象Student，包括了names和nunmber字段

public String mystudent() throws Exception{
 List list=priceService.query();//调用接口实现类
 
 this.jsonUtil(list);
 
 return null;
 }

3、action页面专门写一个方法jsonUtil来做为json方法 

 // 调用json工具方法，传入参数alist
 public void jsonUtil(Object accountlist) throws Exception {
 HttpServletResponse response = ServletActionContext.getResponse();
 log.info("JSON格式：" + accountlist.toString());

 String returnJson = JsonConvert.returnJson(accountlist);
 response.setCharacterEncoding("utf-8");
 response.getWriter().println(returnJson);
 }

4、我用的是一种比较新的json包jackson

import java.io.StringWriter;

import org.codehaus.jackson.map.ObjectMapper;

public class JsonConvert {
 static String jsonStr;
 public static String returnJson(Object object) throws Exception{
 ObjectMapper objectMapper = new ObjectMapper();
 StringWriter stringWriter = new StringWriter();
 objectMapper.writevalue(stringWriter, object);
 
 jsonStr = stringWriter.toString();
 return jsonStr;
 }
}

以上就是本文的全部内容，希望对大家的学习有所帮助。