HttpClient模拟浏览器登录后发起请求
浏览器实现这个效果需要如下几个步骤:
1请求一个需要登录的页面或资源
2服务器判断当前的会话是否包含已登录信息。如果没有登录重定向到登录页面
3手工在登录页面录入正确的账户信息并提交
4服务器判断登录信息是否正确,如果正确则将登录成功信息保存到session中
5登录成功后服务器端给浏览器返回会话的SessionID信息保存到客户端的cookie中
6浏览器自动跳转到之前的请求地址并携带之前的cookie(包含登录成功的SessionID)
7服务器端判断session中是否有成功登录信息,如果有则将请求的资源反馈给浏览器
package com.artsoft.demo;
import java.io.FileOutputStream;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.cookieStore;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.impl.conn.PoolingClientConnectionManager;
import org.apache.http.util.EntityUtils;
public class HttpClientDemo
{
public static void main(String[] args) throws Exception
{
getResoucesByLogincookies();
}
private static void getResoucesByLogincookies() throws Exception
{
HttpClientDemo demo = new HttpClientDemo();
String username = "......";// 登录用户
String password = "......";// 登录密码
// 需要提交登录的信息
String urlLogin = "http://hx.buscoming.cn/Api/Security/Logon?UserCode=" + username + "&Password=" + password;
// 登录成功后想要访问的页面 可以是下载资源 需要替换成自己的iteye Blog地址
String urlAfter = "http://hx.buscoming.cn/Api/Security/GetLoginAccount";
DefaultHttpClient client = new DefaultHttpClient(new PoolingClientConnectionManager());
HttpPost post = new HttpPost(urlLogin);
HttpResponse response = client.execute(post);
HttpEntity entity = response.getEntity();
cookieStore cookieStore = client.getcookieStore();
client.setcookieStore(cookieStore);
HttpGet get = new HttpGet(urlAfter);
response = client.execute(get);
entity = response.getEntity();
String pathName = "d:\index.html";
writeHTMLtoFile(entity, pathName);
}
public static void writeHTMLtoFile(HttpEntity entity, String pathName) throws Exception
{
byte[] bytes = new byte[(int) entity.getContentLength()];
FileOutputStream fos = new FileOutputStream(pathName);
bytes = EntityUtils.toByteArray(entity);
fos.write(bytes);
fos.flush();
fos.close();
}
}
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