Java实现的剪刀石头布游戏示例

本文实例讲述了Java实现的剪刀石头布游戏。分享给大家供大家参考，具体如下：

ChoiceAnswer.java

public class ChoiceAnswer {
    String texts[] = { "石头", "剪刀", "布" };
    int value; // 【1】石头t【2】剪刀t【3】布
    String getText() {
 return texts[value - 1];
    }
    ChoiceAnswer(int value) {
 this.value = value;
    }
    
    int compTo(ChoiceAnswer c) {
 if (value == c.value) {
     return 0;
 }
 if (value + 1 == c.value || (value == 3 && c.value == 1)) {
     return 1;
 }
 return -1;
    }
}

Game.java

import java.util.Scanner;
public class Game {
    void p(String s) {
 System.out.println(s);
    }
    void showWelcome() {
 p("欢迎使用······");
 p("请选择：【1】石头t【2】剪刀t【3】布");
    }
    @SuppressWarnings("resource")
    ChoiceAnswer getUserChoice() {
 Scanner sc = new Scanner(System.in);
 int userChoice = Integer.parseInt(sc.nextLine());
 while (userChoice < 1 || userChoice > 3) {
     p("你输入的不正确！请重新输入！");
     userChoice = Integer.parseInt(sc.nextLine());
 }
 return new ChoiceAnswer(userChoice);
    }
    ChoiceAnswer getComputerChoice() {
 int computerChoice = (int) ((Math.random() * 3) + 1);
 return new ChoiceAnswer(computerChoice);
    }
    void showResult(ChoiceAnswer userChoice, ChoiceAnswer computerChoice) {
 int result = userChoice.compTo(computerChoice);
 if (result == 0) {
     System.out.println("平手,您和电脑均选择了：" + userChoice.getText());
 } else if (result == 1) {
     System.out.println("恭喜,您赢了！您选择了：" + userChoice.getText()
      + ";   电脑选择了：" + computerChoice.getText());
 } else {
     System.out.println("对不起,您败了！您选择了：" + userChoice.getText()
      + ";电脑选择了：" + computerChoice.getText());
 }
    }
    void start() {
 showWelcome();
 ChoiceAnswer userChoice = getUserChoice();
 ChoiceAnswer computerChoice = getComputerChoice();
 showResult(userChoice, computerChoice);
    }
    public static void main(String a[]) {
 System.out.println("考高分网测试结果：");
 new Game().start();
    }
}

运行结果：

更多关于java算法相关内容感兴趣的读者可查看本站专题：《Java数据结构与算法教程》、《Java操作DOM节点技巧总结》、《Java文件与目录操作技巧汇总》和《Java缓存操作技巧汇总》

希望本文所述对大家java程序设计有所帮助。