java编程题之顺时针打印矩阵

本文实例为大家分享了java顺时针打印矩阵的具体代码，供大家参考，具体内容如下

github：剑指offer编程题 

import java.util.ArrayList;


public class Test19 {

 public static void main(String[] args) {
 int[][] array1 = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 }, { 13, 14, 15, 16 } };
 int[][] array2 = { { 1 } };
 int[][] array3 = { { 1 }, { 2 }, { 3 }, { 4 }, { 5 } };
 int[][] array4 = { { 1, 2, 3, 4, 5 } };
 int[][] array5 = { { 1, 2, 3, 4, 5 }, { 6, 7, 8, 9, 10 }, { 11, 12, 13, 14, 15 } };
 printMatrix(array1);
 System.out.println();
 printMatrix(array2);
 System.out.println();
 printMatrix(array3);
 System.out.println();
 printMatrix(array4);
 System.out.println();
 printMatrix(array5);

 }

 public static ArrayList printMatrix(int[][] matrix) {
 ArrayList arrayList = new ArrayList<>();
 int x = 0;
 int row = matrix.length;
 int line = matrix[matrix.length - 1].length;
 while (x < row && x < line) {
  arrayList.addAll(printLine(matrix, x, x, row, line));
  x++;
  row--;
  line--;
 }

 System.out.print(arrayList.toString());
 return arrayList;

 }

 private static ArrayList printLine(int[][] matrix, int r1, int l1, int r2, int l2) {
 ArrayList arrayList = new ArrayList<>();
 for (int i = l1; i <= l2 - 1; i++) {// 保证奇数层中间可输出
  arrayList.add(matrix[r1][i]);
 }

 for (int k = r1 + 1; k <= r2 - 1; k++) {
  arrayList.add(matrix[k][l2 - 1]);
 }
 if ((r2 - r1) != 1) {//防止重复打印
  for (int j = l2 - 2; j >= l1; j--) {
  arrayList.add(matrix[r2 - 1][j]);
  }
 }

 if ((l2 - l1) != 1) {//防止重复打印
  for (int u = r2 - 2; u > r1; u--) {
  arrayList.add(matrix[u][l1]);
  }
 }

 return arrayList;
 }
}
//其他方法

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持考高分网。