Java扑克牌速算24的方法

已知一副扑克牌有54张，去除大王和小王，剩余52张。在其中随机抽取4张牌，利用加减乘除进行计算得到24. 从A到10，他们的值分别为1到10. 从J到K，他们对应的值是减去10以后的值。编写程序生成一副扑克牌，随机抽取4张，进行计算是否能得到24. 如果可以，列出可能的计算表达式，可能有多种计算形式。

主要思想就是先生成除去大小王的52张扑克牌，然后从中随机抽取四张。接着用排列组合的方式找到能计算得到24的表达式。

package Poker;
import java.util.Random;
import java.util.Stack;
public class Poker {
 static int count = 0;
 static int count_2 = 0;
 public static Stack stack = new Stack();
 public static Stack stack_temp = new Stack();
 public static Stack stack_collection = new Stack();
 public static void main(String[] args) {
 System.out.println("Poker World");
 // 生成扑克牌
 int poker[][] = new int[4][13];
 for(int i = 0; i < 4; i++) {
  for(int j = 0; j < 13; j++) {
  if(j + 1 < 11) {
   poker[i][j] = j+1;
  }
  else {
   poker[i][j] = j-9;
  }
  }
 }
 Random r = new Random();
 int randomPoker[] = new int[4];
 for(int i = 0; i < 4; i++) {
  randomPoker[i] = poker[r.nextInt(3)][r.nextInt(12)];
  stack_temp.add(randomPoker[i]);
 }
 System.out.print("抽到的扑克牌：");
 for(int element: randomPoker) {
  System.out.printf("%d ", element);
 }
 System.out.print("n");
 order(randomPoker, 4, 0);
 //System.out.printf("%dn",count_2);
 if(count != 0) {
  System.out.printf("共有%d种计算方法", count);
 }
 else {
  System.out.print("无法计算得到24");
 }
 }
 private static void order(int[] poker, int targ, int cur) {
    // TODO Auto-generated method stub
    if(cur == targ) {
      String str = stack.toString();
      if(!stack_collection.contains(str)) {
stack_collection.add(str);
count_2 += 1;
int new_poker[] = new int[4];
for(int i = 0; i < 4; i++) {
new_poker[i] = stack.pop();
}
for(int i = 3; i >= 0; i--) {
stack.push(new_poker[i]);
}
do24(new_poker);
      }
      return;
    }
    for(int i = 0; i < poker.length; i++) { 
      if(stack_temp.contains(poker[i])) {
stack.add(poker[i]);
for(int j = 0; j < stack_temp.size(); j++) {
if(stack_temp.get(j) == poker[i]) {
 stack_temp.remove(j);
 break;
}
}
 order(poker, targ, cur+1);
 stack.pop();
 stack_temp.add(poker[i]);
      }
    }
 }
    
 public static void do24(int[] poker){
 // 四个数字中间有三个运算符，因此用三重循环遍历。其中0表示+，1表示-，2表示x，3表示÷
 int test[] = {1,2,3,4};
 for(int i=0;i<4;i++){
  for(int j=0;j<4;j++){
  for(int k=0;k<4;k++){
   operate(poker,i,j,k);
   //operate(test,i,j,k);
  }
  }
 }
 
 
 }
 
 public static void operate(int[] poker, int op1, int op2, int op3) {
 int num1 = poker[0];
 int num2 = poker[1];
 int num3 = poker[2];
 int num4 = poker[3];
 if((cal(cal(cal(num1,num2,op1),num3,op2),num4,op3) == 24)) {
  if((((op2 == 0) || (op2 == 1))&&((op3 == 0) || (op3 == 1)))||((op2 != 0) && (op2 != 1))) {
  System.out.println("("+num1+symbol(op1)+num2+")"+symbol(op2)+num3+symbol(op3)+num4);
  count++;
  }
 }
 else if(cal(cal(num1,cal(num2,num3,op2),op1),num4,op3) == 24) {
  if((((op1 == 0) || (op1 == 1))&&((op3 == 0) || (op3 == 1)))||((op1 != 0) && (op1 != 1))) {
  System.out.println(num1+symbol(op1)+"("+num2+symbol(op2)+num3+")"+symbol(op3)+num4);
  count++;
  }
  else {
  System.out.println("["+num1+symbol(op1)+"("+num2+symbol(op2)+num3+")]"+symbol(op3)+num4);
  count++;
  }
 }
 else if(cal(cal(num1,num2,op1),cal(num3,num4,op3),op2) == 24) {
  if((((op1 == 0) || (op1 == 1))&&((op2 == 0) || (op2 == 1)))||((op1 != 0) && (op1 != 1))) {
  System.out.println(num1+symbol(op1)+num2+symbol(op2)+"("+num3+symbol(op3)+num4+")");
  count++;
  }
  else {
  System.out.println("("+num1+symbol(op1)+num2+")"+symbol(op2)+"("+num3+symbol(op3)+num4+")");
  count++;
  }
 }
 else if(cal(cal(cal(num1,num2,op1),num3,op2),num4,op3) == 24) {
  if((((op1 == 0) || (op1 == 1))&&((op2 == 0) || (op2 == 1)))||((op1 != 0) && (op1 != 1))) {
  System.out.println("("+num1+symbol(op1)+num2+symbol(op2)+num3+")"+symbol(op3)+num4);
  count++;
  }
  else {
  System.out.println("[("+num1+symbol(op1)+num2+")"+symbol(op2)+num3+"]"+symbol(op3)+num4);
  count++;
  }
 }
 else if(cal(num1,cal(cal(num2,num3,op2),num4,op3),op1) == 24) {
  if((((op2 == 0) || (op2 == 1))&&((op3 == 0) || (op3 == 1)))||((op2 != 0) && (op2 != 1))) {
  System.out.println(num1+symbol(op1)+"("+num2+symbol(op2)+num3+symbol(op3)+num4+")");
  count++;
  }
  else {
  System.out.println(num1+symbol(op1)+"[("+num2+symbol(op2)+num3+")"+symbol(op3)+num4+"]");
  count++;
  }
 }
 else if(cal(num1,cal(num2,cal(num3,num4,op3),op2),op1) == 24) {
  System.out.println(num1+symbol(op1)+"["+num2+symbol(op2)+"("+num3+symbol(op3)+num4+")]");
  count++;
 }
 }
 
 public static double cal(double num1,double num2,int num){
 double sum=0.0;
 switch(num) {
 case 0:
  sum = num1 + num2;
  break;
 case 1:
  sum = num1 - num2;
  break;
 case 2:
  sum = num1 * num2;
  break;
 case 3:
  if(num1 % num2 == 0) {
  sum = num1 / num2;
  }
  else {
  sum = 999;
  }
  break;
 default:
  break;
 }
 return sum;
 }
 
 public static String symbol(int symbolNum){
 String symbol = "";
 switch (symbolNum) {
 case 0:
  symbol="+";
  break;
 case 1:
  symbol="-";
  break;
 case 2:
  symbol="x";
  break;
 case 3:
  symbol="÷";
  break;
 default:
  break;
 }
 return symbol;
 }
}

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