ajax 防止用户反复提交的2种解决方案

可在服务器端加载方法：
复制代码 代码如下:
private void onLoading()
{
System.Text.StringBuilder sb = new System.Text.StringBuilder();
sb.Append(" function pageLoad(){var manager = Sys.WebForms.PageRequestManager.getInstance(); ");
sb.Append(" manager.add_beginRequest(OnBeginRequest); manager.add_endRequest(OnEndRequest)} var lcPostbackElementID;");
sb.Append(" function onBeginRequest(sender, args){ lcPostbackElementID = args.get_postBackElement().id.toLowerCase(); if (lcPostbackElementID === "btnadwords"){$get("btnAdWords").disabled = true; $get("btnAdWords").value='正在提交...';}} ");
sb.Append(" function onEndRequest(sender, args){if (lcPostbackElementID === "btnadwords"){ $get("btnAdWords").disabled = false; $get("btnAdWords").value='确定';}} ");

scriptManager.RegisterStartupscript(Page, Page.GetType(), "btnAdWords", sb.ToString(), true);
}

也可直接写在页面脚本里：
复制代码 代码如下: