悬浮数字的实现案例

原理是什么呢？

1.获取数字或者状态。
复制代码 代码如下:
function getnewscount(){
        $time = date("Y-m-d",strtotime("-3 day"));
        $where["News.checkked = ?"] = array("val"=>1 , "type"=>1);
        $where["News.UpdateTime >= ?"] = array("val"=>$time,"type"=>1);//'2014-01-10'
        $news = $this->dao_news->getNews($where);
        return count($news);
    }

    function getstatus($user_id){
        $where["lx_messageto.user_id = ?"] = array("val"=>$user_id , "type"=>1);
        $where["lx_messageto.status = ?"] = array("val"=>1,"type"=>1);
        $message = $this->dao_message->getMessageTo($where);
        return count($message);
    }

2.前端处理显示。用js处理。
复制代码 代码如下:

           
           
           
           
           
       

       
           
           
           
           
           
       

css
复制代码 代码如下:
.status_num{
    position:absolute;
    left:70px; top:0px;
    background-image: -webkit-gradient(linear, 0 0, 0 bottom, from(rgba(234, 87, 122, 1)), to(rgba(136, 4, 25, 1)));
    height:30px; line-height:30px;
    vertical-align:middle;
    font-family:Verdana, Geneva, sans-serif; color:#fff;
    font-size:14px;-webkit-border-radius:30px;
    padding:0px 10px; margin-left:20px;
    -webkit-box-shadow:1px 1px 3px #999;}

.status_icon{
    position:absolute;
    left:70px; top:0px;
}

js处理
复制代码 代码如下:
$(function() {
            aMess = $("a[href ^= '/message']");
            aNews = $("a[href ^= '/news/index']");
            var status = $(".status1");
            var statusnews = $(".status2");
            aNews.prepend(statusnews);
            aMess.prepend(status); //处理消息的          
        });

3.或者用ajax获取数据ajax处理
复制代码 代码如下:
$(function() {
            if( $("a[href *= '/news/mgr']") != " " ){
              aNews = $("a[href *= '/news/mgr']") ;
              $.ajax({
                    dataType:'html',
                    type:"POST",
                    url:"/default/index/ajaxgetnewstatus",
                    success:function(msg){
                        if(msg > 0){
                        var num = ''
                                +''+msg+'';
                        aNews.prepend(num);}
                    }
              });
            };
        });