- 11.1 多态基础
- 11.1.1 为何需要多态行为
- 11.1.2 使用虚函数实现多态行为
- 11.1.3 为何需要构造虚函数
- 11.1.4 虚函数的工作原理——理解虚函数表
- 使用sizeof证明虚函数表指针存在
- 11.1.5 抽象基类和纯虚函数
- 11.2 使用虚继承解决菱形问题
- 11.4 使用final来禁止覆盖函数
#includeusing namespace std; class Fish { public: void Swim() { cout << "Fish swims! " << endl; } }; class Tuna :public Fish { public: // override Fish :: Swim void Swim() { cout << "Tuna swims! " << endl; } }; void MakeFishSwim(Fish& inputFish) { // calling Fish :: Swim inputFish.Swim(); } int main() { Tuna myDinner; // calling Tuna: :Swim myDinner.Swim(); // sending Tuna as Fish MakeFishSwim(myDinner); return 0; }
结果如下:
Tuna swims!
Fish swims!
理想情况下,用户希望Tuna对象表现出金枪鱼的行为,即便通过外部函数的Fish参数调用Swim()时亦如此。因此,在MakeFishSwim(Fish& inputFish)函数中调用inputFish.Swim()时,用户希望执行的是Tuna::Swim()。要实现这种多态行为,可将Fish::Swim()声明为虚函数。
调用语法:
class Base
{
virtual ReturnType FunctionName (Parameter List);
};
class Derived
{
ReturnType FunctionName (Parameter List);
};
通过使用关键字 virtual,可确保编译器调用覆盖版本。也就是说,如果 Swim( )被声明为虚函数,则将参数 myFish(其类型为 Fish&)设置为一个 Tuna 对象时, myFish.Swim( )将执行 Tuna::Swim( )。
示例如下:
#includeusing namespace std; class Fish { public: virtual void Swim() //加入virtual关键字,声明为虚函数 { cout << "Fish swims! " << endl; } }; class Tuna :public Fish { public: // override Fish :: Swim void Swim() { cout << "Tuna swims! " << endl; } }; void MakeFishSwim(Fish& inputFish) { // calling Fish :: Swim inputFish.Swim(); } int main() { Tuna myDinner; // calling Tuna: :Swim myDinner.Swim(); // sending Tuna as Fish MakeFishSwim(myDinner); return 0; }
总结:多态就是将派生类对象视为基类对象,并执行派生类的 Swim( )实现。
11.1.3 为何需要构造虚函数对于使用new在自由存储区中实例化的派生类对象,如果将其赋给基类指针,并通过该指针调用delete,将不会调用派生类的析构函数。这可能导致资源未释放、内存泄露等问题。
示例如下:
#includeusing namespace std; class Fish { public: Fish() { cout << "Constructed Fish" << endl; } ~Fish() { cout << "Destroyed Fish" << endl; } }; class Tuna :public Fish { public: Tuna() { cout << "Constructed Tuna" << endl; } ~Tuna() { cout << "Destroyed Tuna" << endl; } }; void DeleteFishMemory(Fish* pFish) { delete pFish; } int main() { cout << "Allocating a Tuna on the free store:" << endl; Tuna* pTuna = new Tuna; cout << "Deleting the Tuna: "<< endl ; DeleteFishMemory(pTuna); cout <<" Instantiating a Tuna on the stack:" << endl; Tuna myDinner; cout << "Automatic destruction as it goes out of scope: " << endl; return 0; }
结果如下:
Allocating a Tuna on the free store:
Constructed Fish
Constructed Tuna
Deleting the Tuna:
Destroyed Fish //仅仅释放了基类对象
Instantiating a Tuna on the stack:
Constructed Fish
Constructed Tuna
Automatic destruction as it goes out of scope:
Destroyed Tuna
Destroyed Fish
要避免上述问题,可将基类中的析构函数声明为虚函数:
#includeusing namespace std; class Fish { public: Fish() { cout << "Constructed Fish" << endl; } virtual ~Fish() { cout << "Destroyed Fish" << endl; } }; class Tuna :public Fish { public: Tuna() { cout << "Constructed Tuna" << endl; } ~Tuna() { cout << "Destroyed Tuna" << endl; } }; void DeleteFishMemory(Fish* pFish) { delete pFish; } int main() { cout << "Allocating a Tuna on the free store:" << endl; Tuna* pTuna = new Tuna; cout << "Deleting the Tuna: "<< endl ; DeleteFishMemory(pTuna); cout <<" Instantiating a Tuna on the stack:" << endl; Tuna myDinner; cout << "Automatic destruction as it goes out of scope: " << endl; return 0; }
结果如下:
Allocating a Tuna on the free store:
Constructed Fish
Constructed Tuna
Deleting the Tuna:
Destroyed Tuna
Destroyed Fish
Instantiating a Tuna on the stack:
Constructed Fish
Constructed Tuna
Automatic destruction as it goes out of scope:
Destroyed Tuna
Destroyed Fish
在编译时,编译器将为Base和Derived类都将有自己的虚函数表(VFT)。实例化这些类的对象时,将创建一个隐藏的指针(VFT*),它指向相应的VFT,可将VFT视为一个包含函数指针的静态数组,其中每个指针都指向相应的虚函数实现。
如上图所示,Derived派生类中除了Func2()外,其它虚函数都有Derived类的本地虚函数实现,Derived 没有覆盖Base::Func2( ),因此相应的函数指针指向 Base 类的 Func2( )实现。
#includeusing namespace std; class SimpleClass { int a, b; public: void DoSomething() { } }; class Base { int a, b; public: virtual void DoSomething() { } }; int main() { cout << "sizeof (SimpleClass) = " << sizeof(SimpleClass) << endl; cout << "sizeof (Base) ="<< sizeof (Base) << endl ; return 0; }
结果如下:
sizeof (SimpleClass) = 8
sizeof (Base) =16
添加关键字virtual带来的影响是,编译器将为Base类生成一个虚函数表,并为其虚函数表指针预留空间。
抽象基类:不能实例化的基类,这样的基类只有一个用途,那就是从它派生出其他类。要创建抽象基类,可声明纯虚函数。
语法如下:
class AbstractBase
{
public:
virtual void DoSomething() = 0;
};
改声明告诉编译器,AbstractBase的派生类必须实现方法DoSomething()
示例代码:
#includeusing namespace std; class Fish { public: // define a pure virtual function Swim virtual void Swim() = 0; }; class Tuna :public Fish { public: void Swim() { cout << "Tuna swims fast in the sea! " << endl; } }; class Carp :public Fish { public: void Swim() { cout << "Carp swims slow in the lake! " << endl; } }; void MakeFishSwim(Fish& inputFish) { inputFish.Swim(); } int main() { // Fish myFish; // Fails, cannot instantiate an ABC Carp myLunch; Tuna myDinner; MakeFishSwim(myLunch); MakeFishSwim(myDinner); return 0; }
结果如下:
Carp swims slow in the lake!
Tuna swims fast in the sea!
编译器不允许创建抽象基类(ABC)Fish的实例,但是抽象基类可以作为指针或者引用的类型输入函数。
按照如下关系图实例化一个鸭嘴兽的类:
示例代码如下:
#includeusing namespace std; class Animal { public: Animal() { cout << "Animal constructor" << endl; } // sample member int age; }; class Mammal :public Animal { }; class Bird :public Animal { }; class Reptile :public Animal { }; class Platypus:public Mammal, public Bird, public Reptile { public: Platypus() { cout << "Platypus constructor" << endl; } }; int main() { Platypus duckBilledP; return 0; }
结果如下:
Animal constructor
Animal constructor
Animal constructor
Platypus constructor
由于采用了多继承,且鸭嘴兽的全部三个基类都是从Animal类派生而来的,因此自动创建了3个Animal实例。
下面采用虚继承方式解决这个问题:
#includeusing namespace std; class Animal { public: Animal() { cout << "Animal constructor" << endl; } // sample member int age; }; class Mammal :public virtual Animal { }; class Bird :public virtual Animal { }; class Reptile :public virtual Animal { }; class Platypus final:public Mammal, public Bird, public Reptile { public: Platypus() { cout << "Platypus constructor" << endl; } }; int main() { Platypus duckBilledP; duckBilledP.age = 25; return 0; }
结果如下:
Animal constructor
Platypus constructor
从 Animal 类派生 Mammal、Bird 和 Reptile 类时,使用了关键字 virtual,这样 Platypus 继承这些类时,每个 Platypus 实例只包含一个 Animal 实例。同时,使用了关键字 final 以禁止将 Platypus 类用作基类。
class Tuna :public Fish
{
public:
// override Fish :: Swim
void Swim() override final
{
cout << "Tuna swims! " << endl;
}
};
class BluefinTuna final : public Tuna
{
public:
void Swim() //Error: Swim() was final in Tuna, cannot override
{
}
};



