LeetCode 1351.统计有序矩阵中的负数（简单）

python

class Solution:
    def countNegatives(self, grid: List[List[int]]) -> int:
        count = 0
        for i in range(len(grid)):
            for j in range(len(grid[i])):
                if(grid[i][j]<0):
                    break
            if(grid[i][j]<0):
                count += len(grid[i]) - j

        return count