python 2018全国自学考试第5章 第30题 一道展示摊销时间的循环题成功了 前面还有20985人

我先规避了输入1月1日是星期几的算式。 用户正常输入星期几。但是我不算。而是用正常泽勒公式运算，其中日期就是1号，直接写1

u_in_year, u_in_day = 2022, 6

for m in range(3, 13):

    k = u_in_year % 100
    j = u_in_year // 100
    h = (1 + ((26 * (m + 1)) // 10) + k + (k // 4) + (j // 4) + (5 * j)) % 7
    if h == 0:
        day_text = "Saturday"
    elif h == 1:
        day_text = "Sunday"
    elif h == 2:
        day_text = "Monday"
    elif h == 3:
        day_text = "Tuesday"
    elif h == 4:
        day_text = "Wednesday"
    elif h == 5:
        day_text = "Thursday"
    elif h == 6:
        day_text = "Thursday"
    print(f"The %d  first {u_in_year} is {day_text}" % (m))

结果如下

少了1月到2月。因为如果加1月或2月。我其他月份就全都算错。测试了很多半法所以就先不含1月和2月 然后今天四月份的星期明显不对应该是周五。这个是怎么回事呢？？？后来发现是把星期四多复制了一下 该题我之前是用4天才做出了。现在是半天已经很快了。但是如何解决1月和2月份的问题呢？？ 终于成功了。兄弟们

u_in_year, u_in_day = 2022, 6

for m in range(1, 13):
    k = u_in_year % 100
    j = u_in_year // 100

    if m == 1 or m == 2:
        m += 12
        a = u_in_year - 1
        k = a % 100
        j = a // 100

    h = (1 + ((26 * (m + 1)) // 10) + k + (k // 4) + (j // 4) + (5 * j)) % 7
    if h == 0:
        day_text = "Saturday星期六"
    elif h == 1:
        day_text = "Sunday星期日"
    elif h == 2:
        day_text = "Monday星期一"
    elif h == 3:
        day_text = "Tuesday星期二"
    elif h == 4:
        day_text = "Wednesday星期三"
    elif h == 5:
        day_text = "Thursday星期四"
    elif h == 6:
        day_text = "Friday星期五"
    print(f"The %2d first %4d is %10s" % (m, u_in_year,day_text))

而且还有排版，美中不足的就是1月和2月。我可以处理但是没有做。而且觉得做的不会太完美， 终于成功了。我找到了两全其美的好办法了

u_in_year, u_in_day = 2022, 6

for m in range(1, 13):
    k = u_in_year % 100
    j = u_in_year // 100

    if m == 1 or m == 2:
        m += 12
        a = u_in_year - 1
        k = a % 100
        j = a // 100
        c = m - 12

    h = (1 + ((26 * (m + 1)) // 10) + k + (k // 4) + (j // 4) + (5 * j)) % 7
    if h == 0:
        day_text = "Saturday星期六"
    elif h == 1:
        day_text = "Sunday星期日"
    elif h == 2:
        day_text = "Monday星期一"
    elif h == 3:
        day_text = "Tuesday星期二"
    elif h == 4:
        day_text = "Wednesday星期三"
    elif h == 5:
        day_text = "Thursday星期四"
    elif h == 6:
        day_text = "Friday星期五"
    if 12 >= m >= 3:
        c = m
    print(f"The %2d first %4d is %10s" % (c, u_in_year, day_text))

成功了 下次再回