栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 软件开发 > 后端开发 > C/C++/C#

【数据结构基础

C/C++/C# 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

【数据结构基础

原题链接:Leetcode 706. Design HashMap

Design a HashMap without using any built-in hash table libraries.

Implement the MyHashMap class:

MyHashMap() initializes the object with an empty map.

  • void put(int key, int value) inserts a (key, value) pair into the HashMap. If the key - already exists in the map, update the corresponding value.
  • int get(int key) returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.
  • void remove(key) removes the key and its corresponding value if the map contains the mapping for the key.

Example 1:

Input
["MyHashMap", "put", "put", "get", "get", "put", "get", "remove", "get"]
[[], [1, 1], [2, 2], [1], [3], [2, 1], [2], [2], [2]]
Output
[null, null, null, 1, -1, null, 1, null, -1]

Explanation
MyHashMap myHashMap = new MyHashMap();
myHashMap.put(1, 1); // The map is now [[1,1]]
myHashMap.put(2, 2); // The map is now [[1,1], [2,2]]
myHashMap.get(1);    // return 1, The map is now [[1,1], [2,2]]
myHashMap.get(3);    // return -1 (i.e., not found), The map is now [[1,1], [2,2]]
myHashMap.put(2, 1); // The map is now [[1,1], [2,1]] (i.e., update the existing value)
myHashMap.get(2);    // return 1, The map is now [[1,1], [2,1]]
myHashMap.remove(2); // remove the mapping for 2, The map is now [[1,1]]
myHashMap.get(2);    // return -1 (i.e., not found), The map is now [[1,1]]

Constraints:

  • 0 <= key, value <= 106
  • At most 104 calls will be made to put, get, and remove.

方法一:链地址法 思路:

链地址法解决冲突

C++代码:
class MyHashMap {
private:
    // 链地址法
    vector>> hash_table;

    // m为设置的质数
    static const int m = 11;

    // 哈希函数
    static int hash(int key) {
        return key % m;
    }

public:
    MyHashMap(): hash_table(m) {}
    
    // 插入键值对
    void put(int key, int value) {
        int h = hash(key);
        for (auto it = hash_table[h].begin(); it != hash_table[h].end(); it++) {
            if ((*it).first == key) {
                (*it).second = value;
                return;
            }
        }
        hash_table[h].push_back(make_pair(key, value));
    }
    
    // 返回值
    int get(int key) {
        int h = hash(key);
        for (auto it = hash_table[h].begin(); it != hash_table[h].end(); it++) {
            if ((*it).first == key) {
                return (*it).second;
            }
        }
        return -1;
    }
    
    // 移除
    void remove(int key) {
        int h = hash(key);
        for (auto it = hash_table[h].begin(); it != hash_table[h].end(); it++) {
            if ((*it).first == key) {
                hash_table[h].erase(it);
                return;
            }
        }
    }
};



转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/1030937.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号