原题链接:Leetcode 706. Design HashMap
Design a HashMap without using any built-in hash table libraries.
Implement the MyHashMap class:
MyHashMap() initializes the object with an empty map.
- void put(int key, int value) inserts a (key, value) pair into the HashMap. If the key - already exists in the map, update the corresponding value.
- int get(int key) returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.
- void remove(key) removes the key and its corresponding value if the map contains the mapping for the key.
Example 1:
Input ["MyHashMap", "put", "put", "get", "get", "put", "get", "remove", "get"] [[], [1, 1], [2, 2], [1], [3], [2, 1], [2], [2], [2]] Output [null, null, null, 1, -1, null, 1, null, -1] Explanation MyHashMap myHashMap = new MyHashMap(); myHashMap.put(1, 1); // The map is now [[1,1]] myHashMap.put(2, 2); // The map is now [[1,1], [2,2]] myHashMap.get(1); // return 1, The map is now [[1,1], [2,2]] myHashMap.get(3); // return -1 (i.e., not found), The map is now [[1,1], [2,2]] myHashMap.put(2, 1); // The map is now [[1,1], [2,1]] (i.e., update the existing value) myHashMap.get(2); // return 1, The map is now [[1,1], [2,1]] myHashMap.remove(2); // remove the mapping for 2, The map is now [[1,1]] myHashMap.get(2); // return -1 (i.e., not found), The map is now [[1,1]]
Constraints:
- 0 <= key, value <= 106
- At most 104 calls will be made to put, get, and remove.
方法一:链地址法 思路:
链地址法解决冲突
C++代码:class MyHashMap {
private:
// 链地址法
vector>> hash_table;
// m为设置的质数
static const int m = 11;
// 哈希函数
static int hash(int key) {
return key % m;
}
public:
MyHashMap(): hash_table(m) {}
// 插入键值对
void put(int key, int value) {
int h = hash(key);
for (auto it = hash_table[h].begin(); it != hash_table[h].end(); it++) {
if ((*it).first == key) {
(*it).second = value;
return;
}
}
hash_table[h].push_back(make_pair(key, value));
}
// 返回值
int get(int key) {
int h = hash(key);
for (auto it = hash_table[h].begin(); it != hash_table[h].end(); it++) {
if ((*it).first == key) {
return (*it).second;
}
}
return -1;
}
// 移除
void remove(int key) {
int h = hash(key);
for (auto it = hash_table[h].begin(); it != hash_table[h].end(); it++) {
if ((*it).first == key) {
hash_table[h].erase(it);
return;
}
}
}
};



