输入一个链表的头节点,从尾到头反过来返回每个节点的值(用数组返回)。
示例 1: 输入:head = [1,3,2] 输出:[2,3,1] 限制: 0 <= 链表长度 <= 10000Python实现
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def reversePrint(self, head):
"""
:type head: ListNode
:rtype: List[int]
"""
self.store=[]
while head:
self.store.append(head.val)
head=head.next
self.store.reverse()
return self.store
使用了列表的reverse()方法,



