[C语言]C语言题目十进制转二进制和计算某一天是该年的第几天

int fun()
{
	int num;
	int i;
	int a[32]={0};
	scanf("%d",&num);
	for (i=0;i<32;i++)
	{
		a[i]=num%2;
		num=num/2;
	}
	for(i=31;i>=0;i--)
	{
		printf("%d",a[i]);
		if (i%4==0)
		{
			printf(" ");
		}
	}
	printf("n");
	return 0;
}

注意,一个函数一个小功能

int leap(int year)
{
	if(	(year%4==0&&year%100!=0)||year%400==0)
	{
		return 1;
	}
	else
	{
		return 0;
	}

}
int jisuan(int year,int month,int day)
{
	int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
	int b[12]={31,29,31,30,31,30,31,31,30,31,30,31};
	int sum=0;
	int i;
	if (leap(year)==1)
	{
		for (i=0;i