java通过for循环排序字母字符

package com.njwb.array;

import java.util.Arrays;
import java.util.Scanner;


public class RowChar {

    public static void main(String[] args) {
        char[] rowChar = {'a','c','u','b','e','p','f','z'};


        Scanner input = new Scanner(System.in);
        System.out.println("原有数组："+ Arrays.toString(rowChar));

        //升序
        char temp;
        for (int i = 0; i < rowChar.length-1; i++) {
            for (int j = 0; j < rowChar.length-1-i; j++) {
                if (rowChar[j] > rowChar[j+1]) {
                    temp = rowChar[j];
                    rowChar[j] = rowChar[j+1];
                    rowChar[j+1] = temp;
                }
            }
        }
        System.out.println("升序后："+Arrays.toString(rowChar));

        System.out.println("输入一个字母：");
        char newChar = input.next().charAt(0);

        char[] newRowChar = new char[rowChar.length+1];

        int index = rowChar.length;
        for (int i = 0; i < rowChar.length; i++) {
            if (rowChar[i] > newChar) {
                index = i;
                break;
            }
        }
        System.out.println("index:"+index);

        for (int i = 0; i < newRowChar.length; i++) {
            if (i
                newRowChar[i] = rowChar[i];
            }else if (i == index){
                newRowChar[i] = newChar;
            }else if (i>index){
                newRowChar[i] = rowChar[i-1];
            }
        }
        System.out.println("升序后："+Arrays.toString(newRowChar));
    }

}

for循环数组rowChar.length得到数组的长度，遍历数组里的每一个值，通过冒泡算法交换字符排序。
如有出入，欢迎指正！！！