实现简单加减乘除计算
代码实现:#include实现结果:int main() { float num1, num2; double result = 0; char ch; printf("输入符号(+、-、*、/):n"); scanf_s("%c", &ch); printf("简易计算器n"); printf("输入两个数:n"); scanf_s("%f%f", &num1, &num2); //使用switch判断是什么符号 switch (ch) { case '+': result = num1 + num2; break; case '-': result = num1 - num2; break; case '*': result = num1 * num2; break; case '/': if (num2 == 0) { printf("Error!"); break; } result = num1 / num2; break; default: printf("Error!"); } printf("%lf", result); }
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