又是学习题解的一天!!!
两次遍历
class Solution {
public int candy(int[] ratings) {
int n = ratings.length;
int[] left = new int[n];
for(int i = 0; i < n; i ++){
if(i > 0 && ratings[i] > ratings[i - 1]){
left[i] = left[i - 1] + 1;
}else{
left[i] = 1;
}
}
int right = 0, ans = 0;
for(int i = n - 1; i >= 0; i --){
if(i < n - 1 && ratings[i] > ratings[i + 1]){
right ++;
}else{
right = 1;
}
ans += Math.max(right, left[i]);
}
return ans;
}
}



