java数组的使用

已有数组保存1,3,5,2,4,6    控制台输出：6 4 2 5 3 1 

        int[] a = new int[]{1,2,3,4,5,6};
        int[] b = new int[a.length];
        for(int i = 0; i

已有数组保存1,5,9,3,5,7，请颠倒数组元素的存放位置并输出
   注意：颠倒后的数组{7,5,3,9,5,1}
   控制台输出：7 5 3 9 5 1

        int[] a= new int[]{1,5,9,3,5,7};
        int[] b = new int[a.length];
        for(int i =0; i

求出数组{15,35,5,-20,60}中的最大值和最小值
   控制台输出：
   最大值：60
   最小值：-20

        int[] a = new int[]{15,35,5,-20,60};
        int max = a[0];
        int min = a[0];
        for(int i = 0;i a[i]){
                min = a[i];
            }
        }
        System.out.println("最大值："+max);
        System.out.println("最小值："+min);

键盘输入10个数，存到数组中，打印奇数位元素的值
   注意：如果数组是{10,11,12,13,14,15},则奇数位元素是10，12，14

        int len = 10;
        int[] arr = new int[len];
        Scanner sc = new Scanner(System.in);
        for(int i = 0;i

有数组{1,22,0,3,44,0,0,5,66,7,0,0,0,88,9}，要求生成一个不包含0的新数组，并控制台遍历该数组，新数组：{1,22,3,44,5,66,7,88,9}

        int[] arr = {1,22,0,3,44,0,0,5,66,7,0,0,0,88,9};
        int count = 0;
        for (int c = 0;c

冒泡排序

int[] arr = {5,8,4,0,3,6};
        for (int i = 0; i < arr.length-1; i++) {
            for (int j = 0; j < arr.length-1-i; j++) {
                if(arr[j] < arr[j+1]){
                    int num = arr[j];
                    arr[j] = arr[j+1];
                    arr[j+1] = num;
                }
            }
        }
        for (int i = 0; i < arr.length; i++) {
            System.out.print(arr[i]+" ");
        }
        System.out.println();

选择排序

int[] a = {5,8,4,0,3,6};
        for(int i=0;i a[j]){
                    int n = a[j];
                    a[j] = a[i];
                    a[i] = n;
                }
            }
        }
        for (int i = 0; i < a.length; i++) {
            System.out.print(a[i]+ " ");
        }