C语言分阶段求利润问题

 （1）用if语句编程序：

#include 
#define M 100000
int main(){
	int a;
	float b;//a代表利润，b代表奖金 
	printf("请输入当月利润：n");
	scanf("%d",&a);
	if(a>M){
		if(a>2*M){
			if(a>4*M){
				if(a>6*M){
					if(a>10*M){
						b=M*0.1+M*0.075+2*M*0.05+2*M*0.03+4*M*0.015+(a-10*M)*0.01;
					}
					else{
						b=M*0.1+M*0.075+2*M*0.05+2*M*0.03+(a-6*M)*0.015;
					}
				}
				else{
					b=M*0.1+M*0.075+2*M*0.05+(a-4*M)*0.03;
				}
			}
			else{
				b=M*0.1+M*0.075+(a-2*M)*0.05;
			}
		}
		else{
			b=M*0.1+(a-M)*0.075;
		}
		
	}
	else{
		b=a*0.1;

	}
	printf("奖金为：%0.2f",b);
}

（2）switch语句：

#include 
#define M 100000
int main(){
	int a,b;
	float c;//a代表利润，c代表奖金 
	printf("请输入当月利润：n");
	scanf("%d",&a);
	b=a/M;
	if(a/M>10){
		b=10;
	}
	
	switch(b){
		case 0:c=a*0.1;break;
		case 1:c=M*0.1+(a-M)*0.075;break;
		case 2:
		case 3:c=M*0.1+M*0.075+(a-M)*0.05;break;
		case 4:
		case 5:c=M*0.1+M*0.075+2*M*0.05+(a-4*M)*0.03;break;
		case 6:
		case 7:
		case 8:
		case 9:c=M*0.1+M*0.075+2*M*0.05+2*M*0.03+(a-6*M)*0.015;break;
		case 10:c=M*0.1+M*0.075+2*M*0.05+2*M*0.03+4*M*0.015+(a-10*M)*0.01;break;	 
	}
	printf("奖金为：%0.2f",c);
	
}