题文
若数列{an}满足:![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/13f7e3d966fb6987827b26424b26505a.gif)
,且对任意正整数m,n都有am+n=am·an,则
![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/12939c5cc18b06e44128c7d7a297ba60.gif)
[ ]
A.![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/59003ad8b7dd7d45250cde15afc44f5d.gif)
B.
![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/a871fc29086c4944d2a7be70304019c5.gif)
C.
![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/54c25f36b94a68de2630252c18372a85.gif)
D.2 题型:未知 难度:其他题型
答案
A解析
该题暂无解析
考点
据考高分专家说,试题“若数列{an}满足:,且对任意正整.....”主要考查你对 [等比数列的前n项和 ]考点的理解。 等比数列的前n项和等比数列的前n项和公式:
等比数列中设元技巧:
已知a1,q,n,an ,Sn中的三个量,求其它两个量,是归结为解方程组问题,知三求二。
注意设元的技巧,如奇数个成等比数列,可设为:…![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/20120829164021819981.png)
,…(公比为q),但偶数个数成等比数列时,不能设为…![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/20120829164021838904.png)
,…因公比不一定为一个正数,公比为正时可如此设。
等比数列前n项和公式的变形:
q≠1时,![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/201208291640218571261.png)
(a≠0,b≠0,a+b=0);
等比数列前n项和常见结论:
一个等比数列有3n项,若前n项之和为S1,中间n项之和为S2,最后n项之和为S3,当q≠-1时,S1,S2,S3为等比数列。


![若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2 若数列{an}满足:,且对任意正整数m,n都有am+n=am·an,则 [ ]A. B. C. D.2](https://www.mshxw.com/file/tupian/20210919/20111223090918001.gif)
