| x-3 |
| 3x2-6x |
| 5 |
| x-2 |
答案:
原式=| x-3 |
| 3x(x-2) |
| x2-4 |
| x-2 |
| 5 |
| x-2 |
=
| x-3 |
| 3x(x-2) |
| x2-9 |
| x-2 |
=
| x-3 |
| 3x(x-2) |
| x-2 |
| (x+3)(x-3) |
=
| 1 |
| 3x(x+3) |
=
| 1 |
| 3(x2+3x) |
∵x2+3x-2=0,
∴x2+3x=2,
∴原式=
| 1 |
| 3×2 |
| 1 |
| 6 |

| x-3 |
| 3x2-6x |
| 5 |
| x-2 |
答案:
原式=| x-3 |
| 3x(x-2) |
| x2-4 |
| x-2 |
| 5 |
| x-2 |
| x-3 |
| 3x(x-2) |
| x2-9 |
| x-2 |
| x-3 |
| 3x(x-2) |
| x-2 |
| (x+3)(x-3) |
| 1 |
| 3x(x+3) |
| 1 |
| 3(x2+3x) |
| 1 |
| 3×2 |
| 1 |
| 6 |