(1)1-
| a-1 |
| a |
| a2-1 |
| a2+2a |
(2)
| x-2 |
| x2 |
| 2 |
| x |
答案:
(1)原式=1-| a-1 |
| a |
| a(a+2) |
| (a+1)(a-1) |
=1-
| a+2 |
| a+1 |
=
| a+1-(a+2) |
| a+1 |
=-
| 1 |
| a+1 |
(2)原式=
| x-2 |
| x2 |
| x-2 |
| x |
=
| x-2 |
| x2 |
| x |
| x-2 |
=
| 1 |
| x |

| a-1 |
| a |
| a2-1 |
| a2+2a |
| x-2 |
| x2 |
| 2 |
| x |
答案:
(1)原式=1-| a-1 |
| a |
| a(a+2) |
| (a+1)(a-1) |
| a+2 |
| a+1 |
| a+1-(a+2) |
| a+1 |
| 1 |
| a+1 |
| x-2 |
| x2 |
| x-2 |
| x |
| x-2 |
| x2 |
| x |
| x-2 |
| 1 |
| x |