| b |
| a |
| a |
| b |
(2)
| a |
| ab2 |
| b |
| a2b |
(3)
| 1 |
| a-b |
| 1 |
| a+b |
(4)m-2+
| 1 |
| m-2 |
(5)
| x |
| x-y |
| x |
| y |
(6)
| m-15 |
| m2-9 |
| 3 |
| 3+m |
答案:
(1)原式=| b2-a2 |
| ab |
| a3-b3 |
| a2b2 |
| a+b+a-b |
| (a-b)(a+b) |
=
| 2a |
| (a-b)(a+b) |
| (m-2)2+1 |
| m-2 |
=
| m2-4m+5 |
| m-2 |
| xy |
| y(x-y) |
| x(x-y) |
| y(x-y) |
=
| xy-x2+xy |
| y(x-y) |
=
| x(2y-x) |
| y(x-y) |
| m-15 |
| (m+3)(m-3) |
| 3(m-3) |
| (m+3)(m-3) |
=
| m-15-3m+9 |
| (m+3)(m-3) |
=
| -2(m+3) |
| (m+3)(m-3) |
=
| 2 |
| 3-m |



