| x2+5x |
| x-1 |
| 2x2+4x |
| x2-x |
答案:
原式=| x2+5x |
| x-1 |
| x(2x+4) |
| x(x-1) |
=
| x2+5x |
| x-1 |
| 2x+4 |
| x-1 |
=
| x2+5x-2x-4 |
| x-1 |
=
| x2+3x-4 |
| x-1 |
=
| (x-1)(x+4) |
| x-1 |
=x+4.
故答案为:x+4.

| x2+5x |
| x-1 |
| 2x2+4x |
| x2-x |
答案:
原式=| x2+5x |
| x-1 |
| x(2x+4) |
| x(x-1) |
| x2+5x |
| x-1 |
| 2x+4 |
| x-1 |
| x2+5x-2x-4 |
| x-1 |
| x2+3x-4 |
| x-1 |
| (x-1)(x+4) |
| x-1 |