| 3 |
| 1+a |
| 6 |
| 1-a |
| 12 |
| a2-1 |
答案:
原式=| 3(a-1) |
| (a+1)(a-1) |
| 6(a+1) |
| (a+1)(a-1) |
| 12 |
| (a+1)(a-1) |
=
| 3(a-1)+6(a+1)-12 |
| (a+1)(a-1) |
=
| 9(a-1) |
| (a+1)(a-1) |
=
| 9 |
| a+1 |

| 3 |
| 1+a |
| 6 |
| 1-a |
| 12 |
| a2-1 |
答案:
原式=| 3(a-1) |
| (a+1)(a-1) |
| 6(a+1) |
| (a+1)(a-1) |
| 12 |
| (a+1)(a-1) |
| 3(a-1)+6(a+1)-12 |
| (a+1)(a-1) |
| 9(a-1) |
| (a+1)(a-1) |
| 9 |
| a+1 |