计算(lg8+lg1000)*lg5+3(lg2)+lg6(负一次方)+lg0.006

学习 时间:2026-06-05 23:26:53 阅读:8437
计算(lg8+lg1000)*lg5+3(lg2)+lg6(负一次方)+lg0.006

最佳回答

甜甜的镜子

眯眯眼的汉堡

2026-06-05 23:26:53

=(3lg2+3lg10)lg5+3(lg2)^2-lg6+lg6-3lg1 =(3lg2+3lg2+3lg5)lg5+3(lg2)^2 =6lg2lg5+3(lg5)^2+3(lg2)^2 =3 ( (lg2)^2+2lg2lg5+(lg2)^2 ) =3 (lg2+lg5)^2 =3

最新回答共有2条回答

  • 生动的金毛
    回复
    2026-06-05 23:26:53

    =(3lg2+3lg10)lg5+3(lg2)^2-lg6+lg6-3lg1 =(3lg2+3lg2+3lg5)lg5+3(lg2)^2 =6lg2lg5+3(lg5)^2+3(lg2)^2 =3 ( (lg2)^2+2lg2lg5+(lg2)^2 ) =3 (lg2+lg5)^2 =3

上一篇 There were two small rooms in the beach house,------served a

下一篇 应该如何挑选木地板