第九章分式加减,计算题= =如图.第二小题,

原式=(a²+3)/[(a+1)(a-1)]-(a+1)/(a-1)+1=[(a²+3)-(a+1)²+a²-1]/[(a+1)(a-1)]=[a²+3-a²-2a-1+a²-1]/[(a+1)(a-1)]=(a²-2a+1)/[(a+1)(a-1)]=(a-1)²/[(a+1)(a-1)]=(a-1)/(a+1)第一题 你做得对