设计一个关于复数的结构类型,并实现复数的四则运算

#include
struct fushu
{
int x,y;
};
void count(struct fushu *m,struct fushu *n);
void main()
{
struct fushu m,n;
printf("Please input the first num:\n");
scanf("%d%di",&m。x,&m。y);
printf("Please input the second num:\n");
scanf("%d%di",&n。x,&n。y);
count(&m,&n);
}
void count(struct fushu *m,struct fushu *n)
{
int fuhao;
printf("input the sign 1:+,2:-,3:*,4:/");
scanf("%d",&fuhao);
switch (fuhao){
case 1:
{
if((m->y+n->y)>=0)
printf("%d+%di",(m->x+n->x),(m->y+n->y));
else
printf("%d%di",(m->x+n->x),(m->y+n->y));
}
break;
case 2:
if((m->y+n->y)>=0)
printf("%d+%di",(m->x-n->x),(m->y-n->y));
else
printf("%d%di",(m->x-n->x),(m->y-n->y));
break;
case 3:
if((m->y+n->y)x*n->x),(m->y*n->y));
else
printf("%d%di",(m->x*n->x),(m->y*n->y));
break;
case 4:
if((m->y+n->y)x/n->x),(m->y/n->y));
else
printf("%d%di",(m->x/n->x),(m->y/n->y));
break;
default:
printf("Error sign");
}
}