(1)x²-1/x²+4x+4÷(x+1)乘x+2/1-x

学习 时间:2026-03-30 11:41:02 阅读:10000
(1)x²-1/x²+4x+4÷(x+1)乘x+2/1-x(3)(2xy分之-mn)²÷8x²/y²乘(-2m分之y²)³ (2)(xy-x²)÷x²-2xy+y²/xy乘x-y/x²

最佳回答

温婉的猎豹

灵巧的云朵

2026-03-30 11:41:02

(1)(x²-1)/(x²+4x+4)÷(x+1)*(x+2)/(1-x)
=(x+1)(x-1)/(x+2)²*1/(x+1)*(x+2)/(1-x)
=-1/(x+2)
(2)
(xy-x²)÷(x²-2xy+y²)/xy*(x-y)/x²
=-x(x-y)÷(x-y)²/xy*(x-y)/x²
=-x(x-y)*xy/(x-y)²*(x-y)/x²
=-y
(3)
原式
=(-mn/2xy)²*y²/8x²*(-y²/2m)³
=m²n²/4x²y²*y²/8x²*(-y^6/8m³)
=-m²n²/4x²y²*y²/8x²*y^6/8m³
=n²y^6/(256mx⁴)

最新回答共有2条回答

  • 感性的老虎
    回复
    2026-03-30 11:41:02

    (1)(x²-1)/(x²+4x+4)÷(x+1)*(x+2)/(1-x)=(x+1)(x-1)/(x+2)²*1/(x+1)*(x+2)/(1-x)=-1/(x+2)(2)(xy-x²)÷(x²-2xy+y²)/xy*(x-y)/x²=-x(x-y)÷(x-y)²/xy*(x-y)/x²=-x(x-y)*xy/(x-y)²*(x-y)/x²=-y(3)原式=(-mn/2xy)²*y²/8x²*(-y²/2m)³ =m²n²/4x²y²*y²/8x²*(-y^6/8m³)=-m²n²/4x²y²*y²/8x²*y^6/8m³=n²y^6/(256mx⁴)

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