集合A={x|x²-[2a+(a²+1)]x+2a(a²+1)≤0},B=｛x|(x-2)

①(x-2a)[x-(a²+1)]≤0;∵a²+1≥2a;∴ 2a≤x≤a²+1;②当a>1/3;(x-2)[x-(3a+1)]≤0; 2≤x≤3a+1;∴2a≥2; 3a+1≥a²+1∴1≤a≤3③ 当a≤1/3;(x-2)[x-(3a+1)]≤0; 3a+1≤x≤2;∴2a≥3a+1; 2≥a²+1;∴a=-1;∴综上得：a=-1或1≤a≤3